Iteration

Sum Problems

Lesson

A common type of problem is to find all possible sets of numbers that sum to a target. Here's an example of this:

Problem: Print out all positive integers a, b, and c that sum to the number 10.

a + b + c = 10\notag \large \texttt{a + b + c = 10}

You might think to do a brute force solution like this:

Time Complexity O(n3)O(n^3). We have a triple for-loop.

Space Complexity O(1)O(1).

But you can actually do much better than brute-force. Whenever you see a problem like this, you can always write one of the variables using the other variables. Here, you can subtract a and b from both sides of the equation to solve for c, like this:

c = 10 - a - b\notag \large \texttt{c = 10 - a - b}

This equation tells you that the value of c is completely determined by the values of a and b. This is because c = 10 - a - b. This means we don't need to loop over it. Here's the above code, but where we removed the for-loop over c:

Time Complexity O(n2)O(n^2). We have a double for-loop.

Space Complexity O(1)O(1).

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